Remove empty lines

[Davider]

In the following code, using the replacerx function always takes effect, but using the findreplace function sometimes does not take effect.
I want to use the findreplace function because it has lower resource consumption.

Macro Macro17

Code:

Copy      Help

out

_s=
;Node,ReleaseDate,SMBIOSBIOSVersion
;
;DESKTOP-3URCFPT,20131216000000.000000+000,F1

_s.trim; _s.findreplace("[][]", "[]") ;;Sometimes does not take effect
;_s.replacerx("\r\n?\r\n" "[]") ;;Always takes effect
out _s

[Davider]

The following code always works. Is there a more concise way to write it? 

The cause of issue #1 is that, in some cases, the line break is \r instead of \r\n.
 

Code:

Copy      Help

_s=
;Node,ReleaseDate,SMBIOSBIOSVersion
;
;Node,ReleaseDate,SMBIOSBIOSVersion
;
;DESKTOP-3URCFPT,20131216000000.000000+000,F1

str b=
;
;
;
_s.trim; _s.findreplace(b, "[]")

---

The problem is solved, but there might be a better way. 

Code:

Copy      Help

_s.findreplace("[13][10][13][10]", "[]")
_s.findreplace("[13][13][10]", "[]")